Matematika tolong dibantu no 2 sampai 5 pakai caranya. terimakasih...​

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tolong dibantu no 2 sampai 5 pakai caranya. terimakasih...​ Jawaban: maaff ya kalo salhhhhhhhhh Materi : Pecahan Soal Nomor 2 Bagian B 0,58 + 1,2 + 6/15 - 1,6 = 0,58 + 1,20 + 0,20 + 1,60 = (0+1),(5+2+2+6)(8+0+0+0) = 1,(15)(8) = (1+1),(5)(8) = 2,58 Bagian C 0,42 ÷ 0,6 - 0,65 × 1/13 = 42/10 × 10/6 - 65/100 × 1/13 = 42/6 - 5/100 = 7 - 0,05 = 6,95 Soal Nomor 3 Bagian A 2 - 0,68 + 1,25 ÷ 0,5 = 1,32 + 125/100 × 10/5 = 1,32 + 25/10 = 1,32 + 2,5 = 3,82 Bagian B 0,4 × 1,26 + 0,72 ÷ 8 = 4/10 × 126/100 + 72/100 × ⅛ = 4(126)/1000 + 9/100 = 504/1000 + 9/100 = 0,504 + 0,09 = 0,594 Bagian C 9 × 0,2 - 1,6 ÷ 4 = 9 × 2/10 - 16/10 × ¼ = 18/10 - 4/10 = 1,8 - 0,4 = 1,4 Soal Nomor 4 K = 2( p + l ) 3K = ( 2 × 3 )( 12 m + 8,5 m ) 3K = 6( 20,5 m ) 3K = 120 + 3,0 m 3K = 123 m Soal Nomor 5 3,5 + 1¼ - 2 - 2,5 = ( 3 + 1 - 2 - 2 ),(5+2-5)(0+5-0) = ( 4 - 4 ),(2)(5) = 0,25 Semoga bisa membantu [tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex] [answer.2.content]
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